Find Transpose of a Matrix using C++

In this program asks user to enter a matrix (size of matrix is specified by user) and this program finds the transpose of that matrix and displays it.

Source Code to Find Transpose of a Matrix

#include <iostream>
using namespace std;
int main()
{
    int a[10][10], trans[10][10], r, c, i, j;
    cout << "Enter rows and columns of matrix: ";
    cin >> r >> c;

/* Storing element of matrix entered by user in array a[][]. */
    cout << endl << "Enter elements of matrix: " << endl;
    for(i=0; i<r; ++i)
    for(j=0; j<c; ++j)
    {
        cout << "Enter elements a" << i+1 << j+1 << ": ";
        cin >> a[i][j];
    }
/* Displaying the matrix a[][] */
    cout << endl << "Entered Matrix: " << endl;
    for(i=0; i<r; ++i)
    for(j=0; j<c; ++j)
    {
        cout << " " << a[i][j];
        if(j==c-1)
            cout << endl << endl;
    }

/* Finding transpose of matrix a[][] and storing it in array trans[][]. */
    for(i=0; i<r; ++i)
    for(j=0; j<c; ++j)
    {
       trans[j][i]=a[i][j];
    }

/* Displaying the transpose,i.e, Displaying array trans[][]. */
    cout << endl << "Transpose of Matrix: " << endl;
    for(i=0; i<c; ++i)
    for(j=0; j<r; ++j)
    {
        cout << " " << trans[i][j];
        if(j==r-1)
            cout << endl << endl;
    }
    return 0;
}

Output

Enter rows and column of matrix: 2
3

Enter elements of matrix:
Enter elements a11: 1
Enter elements a12: 2
Enter elements a13: 9
Enter elements a21: 0
Enter elements a22: 4
Enter elements a23: 7

Entered Matrix:
1  2  9

0  4  7


Transpose of Matrix:
1  0

2  4

9  7